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\int \sin(x)\mathrm{d}x
Evaluate the indefinite integral first.
-\cos(x)
Use \int \sin(x)\mathrm{d}x=-\cos(x) from the table of common integrals to obtain the result.
-\cos(\frac{1}{2}\pi )+\cos(\frac{1}{6}\pi )
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{\sqrt{3}}{2}
Simplify.