Solve ∫ 436x^435 wrt x

$$\int 436 x ^ { 435 } d x$$

Evaluate

$$x^{436}+С$$

Solution Steps

Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.

$$436\int x^{435}\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{435}\mathrm{d}x with \frac{x^{436}}{436}. Multiply 436 times \frac{x^{436}}{436}.

$$x^{436}$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$x^{436}+С$$

Differentiate w.r.t. x

$$436x^{435}$$