Evaluate
Tx^{2}+Сx+С_{1}
Differentiate w.r.t. x
2Tx+С
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2\int \int T\mathrm{d}x\mathrm{d}x
Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.
2\left(\frac{Tx^{2}}{2}+Сx\right)
Simplify.
Tx^{2}+Сx
Simplify.
Tx^{2}+Сx+С
If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.
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