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Differentiate w.r.t. x
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\int 6x^{2}+4x-15x-10\mathrm{d}x
Apply the distributive property by multiplying each term of 2x-5 by each term of 3x+2.
\int 6x^{2}-11x-10\mathrm{d}x
Combine 4x and -15x to get -11x.
\int 6x^{2}\mathrm{d}x+\int -11x\mathrm{d}x+\int -10\mathrm{d}x
Integrate the sum term by term.
6\int x^{2}\mathrm{d}x-11\int x\mathrm{d}x+\int -10\mathrm{d}x
Factor out the constant in each of the terms.
2x^{3}-11\int x\mathrm{d}x+\int -10\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}. Multiply 6 times \frac{x^{3}}{3}.
2x^{3}-\frac{11x^{2}}{2}+\int -10\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply -11 times \frac{x^{2}}{2}.
2x^{3}-\frac{11x^{2}}{2}-10x
Find the integral of -10 using the table of common integrals rule \int a\mathrm{d}x=ax.
2x^{3}-\frac{11x^{2}}{2}-10x+С
If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.