Solve ∫ (2x^3+5)^3

$$\int ( 2 x ^ { 3 } + 5 ) ^ { 3 }$$

Evaluate

$$\frac{4x^{10}}{5}+\frac{60x^{7}}{7}+\frac{75x^{4}}{2}+125x+С$$

Solution Steps

Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(2x^{3}+5\right)^{3}.

$$\int 8\left(x^{3}\right)^{3}+60\left(x^{3}\right)^{2}+150x^{3}+125\mathrm{d}x$$

To raise a power to another power, multiply the exponents. Multiply 3 and 3 to get 9.

$$\int 8x^{9}+60\left(x^{3}\right)^{2}+150x^{3}+125\mathrm{d}x$$

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$\int 8x^{9}+60x^{6}+150x^{3}+125\mathrm{d}x$$

Integrate the sum term by term.

$$\int 8x^{9}\mathrm{d}x+\int 60x^{6}\mathrm{d}x+\int 150x^{3}\mathrm{d}x+\int 125\mathrm{d}x$$

Factor out the constant in each of the terms.

$$8\int x^{9}\mathrm{d}x+60\int x^{6}\mathrm{d}x+150\int x^{3}\mathrm{d}x+\int 125\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{9}\mathrm{d}x with \frac{x^{10}}{10}. Multiply 8 times \frac{x^{10}}{10}.

$$\frac{4x^{10}}{5}+60\int x^{6}\mathrm{d}x+150\int x^{3}\mathrm{d}x+\int 125\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{6}\mathrm{d}x with \frac{x^{7}}{7}. Multiply 60 times \frac{x^{7}}{7}.

$$\frac{4x^{10}}{5}+\frac{60x^{7}}{7}+150\int x^{3}\mathrm{d}x+\int 125\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{3}\mathrm{d}x with \frac{x^{4}}{4}. Multiply 150 times \frac{x^{4}}{4}.

$$\frac{4x^{10}}{5}+\frac{60x^{7}}{7}+\frac{75x^{4}}{2}+\int 125\mathrm{d}x$$

Find the integral of 125 using the table of common integrals rule \int a\mathrm{d}x=ax.

$$\frac{4x^{10}}{5}+\frac{60x^{7}}{7}+\frac{75x^{4}}{2}+125x$$

Simplify.

$$125x+\frac{75x^{4}}{2}+\frac{60x^{7}}{7}+\frac{4x^{10}}{5}$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$125x+\frac{75x^{4}}{2}+\frac{60x^{7}}{7}+\frac{4x^{10}}{5}+С$$

Differentiate w.r.t. x

$$\left(2x^{3}+5\right)^{3}$$