Solve ∫ (-4+3)^2-1^2

$$\int ( - 4 + 3 ) ^ { 2 } - 1 ^ { 2 }$$

Evaluate

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Solution Steps

Add -4 and 3 to get -1.

$$\int \left(-1\right)^{2}-1^{2}\mathrm{d}x$$

Calculate -1 to the power of 2 and get 1.

$$\int 1-1^{2}\mathrm{d}x$$

Calculate 1 to the power of 2 and get 1.

$$\int 1-1\mathrm{d}x$$

Subtract 1 from 1 to get 0.

$$\int 0\mathrm{d}x$$

Find the integral of 0 using the table of common integrals rule \int a\mathrm{d}x=ax.

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If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

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Differentiate w.r.t. x

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