Evaluate
\frac{md^{2}}{3}+С
Differentiate w.r.t. d
\frac{2dm}{3}
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\left(\frac{\sqrt{3}d}{3}\right)^{2}m
Find the integral of \left(\frac{\sqrt{3}d}{3}\right)^{2} using the table of common integrals rule \int a\mathrm{d}m=am.
\frac{d^{2}m}{3}
Simplify.
\frac{d^{2}m}{3}+С
If F\left(m\right) is an antiderivative of f\left(m\right), then the set of all antiderivatives of f\left(m\right) is given by F\left(m\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.
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