Evaluate
\frac{2x^{\frac{3}{2}}}{3}+С
Differentiate w.r.t. x
\sqrt{x}
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\frac{2x^{\frac{3}{2}}}{3}
Rewrite \sqrt{x} as x^{\frac{1}{2}}. Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{\frac{1}{2}}\mathrm{d}x with \frac{x^{\frac{3}{2}}}{\frac{3}{2}}. Simplify.
\frac{2x^{\frac{3}{2}}}{3}+С
If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.
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