Evaluate
7\sqrt{6}h+С
Differentiate w.r.t. h
7 \sqrt{6} = 17.146428199
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\sqrt{294}h
Find the integral of \sqrt{294} using the table of common integrals rule \int a\mathrm{d}h=ah.
7\sqrt{6}h
Simplify.
7\sqrt{6}h+С
If F\left(h\right) is an antiderivative of f\left(h\right), then the set of all antiderivatives of f\left(h\right) is given by F\left(h\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.
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