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Evaluate
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Differentiate w.r.t. x
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\int \sqrt{-3}x\mathrm{d}x
Subtract 4 from 1 to get -3.
\sqrt{-3}\int x\mathrm{d}x
Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.
\sqrt{-3}\times \frac{x^{2}}{2}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}.
\text{Indeterminate}
Simplify.