Solve for x
x=\frac{С}{y^{2}+2}
Solve for y
\left\{\begin{matrix}y=\frac{\sqrt{\frac{С}{x}-8}}{2}\text{; }y=-\frac{\sqrt{\frac{С}{x}-8}}{2}\text{, }&\left(x>0\text{ and }x\leq С\right)\text{ or }\left(x\geq С_{1}\text{ and }x<0\right)\\y\in \mathrm{R}\text{, }&x=0\text{ and }С=0\end{matrix}\right.
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