Solve ∫ wrt x/1+(sqrt{3)^2}

$$\int \frac { d x } { 1 + ( \sqrt { 3 } ) ^ { 2 } }$$

Evaluate

$$\frac{x}{4}+С$$

Solution Steps

The square of \sqrt{3} is 3.

$$\int \frac{1}{1+3}\mathrm{d}x$$

Add 1 and 3 to get 4.

$$\int \frac{1}{4}\mathrm{d}x$$

Find the integral of \frac{1}{4} using the table of common integrals rule \int a\mathrm{d}x=ax.

$$\frac{x}{4}$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$\frac{x}{4}+С$$

Differentiate w.r.t. x

$$\frac{1}{4} = 0.25$$