Solve ∫ dh/k_{1-k_{2}}

$$\int \frac { d h } { k _ { 1 } - k _ { 2 } }$$

Evaluate

$$\frac{h}{k_{1}-k_{2}}+С$$

Solution Steps

Find the integral of \frac{1}{k_{1}-k_{2}} using the table of common integrals rule \int a\mathrm{d}h=ah.

$$\frac{h}{k_{1}-k_{2}}$$

If F\left(h\right) is an antiderivative of f\left(h\right), then the set of all antiderivatives of f\left(h\right) is given by F\left(h\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$\frac{h}{k_{1}-k_{2}}+С$$

Differentiate w.r.t. k_1

$$-\frac{h}{\left(k_{1}-k_{2}\right)^{2}}$$