Evaluate
\frac{xd^{z}}{\sqrt{z}+1}+С
Differentiate w.r.t. x
\frac{d^{z}}{\sqrt{z}+1}
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\frac{d^{z}}{1+\sqrt{z}}x
Find the integral of \frac{d^{z}}{1+\sqrt{z}} using the table of common integrals rule \int a\mathrm{d}x=ax.
\frac{d^{z}x}{1+\sqrt{z}}
Simplify.
\frac{d^{z}x}{1+\sqrt{z}}+С
If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.
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