Evaluate
\frac{6x^{\frac{5}{3}}}{25}+С
Differentiate w.r.t. x
\frac{2x^{\frac{2}{3}}}{5}
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\frac{2\int x^{\frac{2}{3}}\mathrm{d}x}{5}
Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.
\frac{6x^{\frac{5}{3}}}{25}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{\frac{2}{3}}\mathrm{d}x with \frac{3x^{\frac{5}{3}}}{5}.
\frac{6x^{\frac{5}{3}}}{25}+С
If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.
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