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Differentiate w.r.t. x
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\int \frac{2\left(3x-1\right)\left(3x+1\right)}{3x-1}\mathrm{d}x
Factor the expressions that are not already factored in \frac{18x^{2}-2}{3x-1}.
\int 2\left(3x+1\right)\mathrm{d}x
Cancel out 3x-1 in both numerator and denominator.
\int 6x+2\mathrm{d}x
Expand the expression.
\int 6x\mathrm{d}x+\int 2\mathrm{d}x
Integrate the sum term by term.
6\int x\mathrm{d}x+\int 2\mathrm{d}x
Factor out the constant in each of the terms.
3x^{2}+\int 2\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply 6 times \frac{x^{2}}{2}.
3x^{2}+2x
Find the integral of 2 using the table of common integrals rule \int a\mathrm{d}x=ax.
3x^{2}+2x+С
If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.