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4\int \cos(4x)\mathrm{d}x=\sin(4x)+4C
Multiply both sides of the equation by 4.
\sin(4x)+4C=4\int \cos(4x)\mathrm{d}x
Swap sides so that all variable terms are on the left hand side.
4C=4\int \cos(4x)\mathrm{d}x-\sin(4x)
Subtract \sin(4x) from both sides.
4C=4x\cos(4x)-\sin(4x)+4С
The equation is in standard form.
\frac{4C}{4}=\frac{4x\cos(4x)-\sin(4x)+С}{4}
Divide both sides by 4.
C=\frac{4x\cos(4x)-\sin(4x)+С}{4}
Dividing by 4 undoes the multiplication by 4.