Solve d/dxleft((4x-1)(3x+2)right)

$$\frac{d}{d x } \left((4x-1)(3x+2) \right)$$

Evaluate

$$24x+5$$

Steps Using Derivative Rule for Product

For any two differentiable functions, the derivative of the product of two functions is the first function times the derivative of the second plus the second function times the derivative of the first.

$$\left(4x^{1}-1\right)\frac{\mathrm{d}}{\mathrm{d}x}(3x^{1}+2)+\left(3x^{1}+2\right)\frac{\mathrm{d}}{\mathrm{d}x}(4x^{1}-1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$\left(4x^{1}-1\right)\times 3x^{1-1}+\left(3x^{1}+2\right)\times 4x^{1-1}$$

Simplify.

$$\left(4x^{1}-1\right)\times 3x^{0}+\left(3x^{1}+2\right)\times 4x^{0}$$

Multiply 4x^{1}-1 times 3x^{0}.

$$4x^{1}\times 3x^{0}-3x^{0}+\left(3x^{1}+2\right)\times 4x^{0}$$

Multiply 3x^{1}+2 times 4x^{0}.

$$4x^{1}\times 3x^{0}-3x^{0}+3x^{1}\times 4x^{0}+2\times 4x^{0}$$

To multiply powers of the same base, add their exponents.

$$3\times 4x^{1}+3\left(-1\right)x^{0}+3\times 4x^{1}+2\times 4x^{0}$$

Simplify.

$$12x^{1}-3x^{0}+12x^{1}+8x^{0}$$

Combine like terms.

$$\left(12+12\right)x^{1}+\left(-3+8\right)x^{0}$$

Add 12 to 12.

$$24x^{1}+\left(-3+8\right)x^{0}$$

Add -3 to 8.

$$24x^{1}+5x^{0}$$

For any term t, t^{1}=t.

$$24x+5x^{0}$$

For any term t except 0, t^{0}=1.

$$24x+5\times 1$$

For any term t, t\times 1=t and 1t=t.

$$24x+5$$

Differentiate w.r.t. x

$$24$$