Solve y+1/frac{2{3}}=x

$$\frac{ y+1 }{ \frac{ 2 }{ 3 } } = x$$

Solve for y

$$y=\frac{2x}{3}-1$$

Steps for Solving Linear Equation

Divide each term of y+1 by \frac{2}{3} to get \frac{y}{\frac{2}{3}}+\frac{1}{\frac{2}{3}}.

$$\frac{y}{\frac{2}{3}}+\frac{1}{\frac{2}{3}}=x$$

Divide 1 by \frac{2}{3} by multiplying 1 by the reciprocal of \frac{2}{3}.

$$\frac{y}{\frac{2}{3}}+1\times \frac{3}{2}=x$$

Multiply 1 and \frac{3}{2} to get \frac{3}{2}.

$$\frac{y}{\frac{2}{3}}+\frac{3}{2}=x$$

Subtract \frac{3}{2} from both sides.

$$\frac{y}{\frac{2}{3}}=x-\frac{3}{2}$$

The equation is in standard form.

$$\frac{3}{2}y=x-\frac{3}{2}$$

Divide both sides of the equation by \frac{3}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{2}y}{\frac{3}{2}}=\frac{x-\frac{3}{2}}{\frac{3}{2}}$$

Dividing by \frac{3}{2} undoes the multiplication by \frac{3}{2}.

$$y=\frac{x-\frac{3}{2}}{\frac{3}{2}}$$

Divide x-\frac{3}{2} by \frac{3}{2} by multiplying x-\frac{3}{2} by the reciprocal of \frac{3}{2}.

$$y=\frac{2x}{3}-1$$

Solve for x

$$x=\frac{3\left(y+1\right)}{2}$$