Solve x-z/y=1/2

$$\frac{ x-z }{ y } = \frac{ 1 }{ 2 }$$

Solve for x

$$x=\frac{y}{2}+z$$

$$y\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2y, the least common multiple of y,2.

$$2\left(x-z\right)=y$$

Use the distributive property to multiply 2 by x-z.

$$2x-2z=y$$

Add 2z to both sides.

$$2x=y+2z$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{y+2z}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{y+2z}{2}$$

Divide y+2z by 2.

$$x=\frac{y}{2}+z$$

Solve for y

$$y=2\left(x-z\right)$$

$$x\neq z$$

Solution Steps

Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 2y, the least common multiple of y,2.

$$2\left(x-z\right)=y$$

Use the distributive property to multiply 2 by x-z.

$$2x-2z=y$$

Swap sides so that all variable terms are on the left hand side.

$$y=2x-2z$$

Variable y cannot be equal to 0.

$$y=2x-2z\text{, }y\neq 0$$