Solve x-5/2x+4>0

$$\frac{ x-5 }{ 2x+4 } > 0$$

Solve for x

$$x\in \left(-\infty,-2\right)\cup \left(5,\infty\right)$$

Solution Steps

For the quotient to be positive, x-5 and 2x+4 have to be both negative or both positive. Consider the case when x-5 and 2x+4 are both negative.

$$x-5<0 2x+4<0$$

The solution satisfying both inequalities is x<-2.

$$x<-2$$

Consider the case when x-5 and 2x+4 are both positive.

$$2x+4>0 x-5>0$$

The solution satisfying both inequalities is x>5.

$$x>5$$

The final solution is the union of the obtained solutions.

$$x<-2\text{; }x>5$$