Solve x-4/20-4=5-0/16-0

$$\frac{ x-4 }{ 20-4 } = \frac{ 5-0 }{ 16-0 }$$

Solve for x

$$x=9$$

Steps for Solving Linear Equation

Subtract 4 from 20 to get 16.

$$\frac{x-4}{16}=\frac{5-0}{16-0}$$

Subtract 0 from 5 to get 5.

$$\frac{x-4}{16}=\frac{5}{16-0}$$

Subtract 0 from 16 to get 16.

$$\frac{x-4}{16}=\frac{5}{16}$$

Divide each term of x-4 by 16 to get \frac{1}{16}x-\frac{1}{4}.

$$\frac{1}{16}x-\frac{1}{4}=\frac{5}{16}$$

Add \frac{1}{4} to both sides.

$$\frac{1}{16}x=\frac{5}{16}+\frac{1}{4}$$

Least common multiple of 16 and 4 is 16. Convert \frac{5}{16} and \frac{1}{4} to fractions with denominator 16.

$$\frac{1}{16}x=\frac{5}{16}+\frac{4}{16}$$

Since \frac{5}{16} and \frac{4}{16} have the same denominator, add them by adding their numerators.

$$\frac{1}{16}x=\frac{5+4}{16}$$

Add 5 and 4 to get 9.

$$\frac{1}{16}x=\frac{9}{16}$$

Multiply both sides by 16, the reciprocal of \frac{1}{16}.

$$x=\frac{9}{16}\times 16$$

Cancel out 16 and 16.

$$x=9$$