Solve for x
x=-1
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\frac{1}{3}x-\frac{2}{3}=x
Divide each term of x-2 by 3 to get \frac{1}{3}x-\frac{2}{3}.
\frac{1}{3}x-\frac{2}{3}-x=0
Subtract x from both sides.
-\frac{2}{3}x-\frac{2}{3}=0
Combine \frac{1}{3}x and -x to get -\frac{2}{3}x.
-\frac{2}{3}x=\frac{2}{3}
Add \frac{2}{3} to both sides. Anything plus zero gives itself.
x=\frac{2}{3}\left(-\frac{3}{2}\right)
Multiply both sides by -\frac{3}{2}, the reciprocal of -\frac{2}{3}.
x=\frac{2\left(-3\right)}{3\times 2}
Multiply \frac{2}{3} times -\frac{3}{2} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-3}{3}
Cancel out 2 in both numerator and denominator.
x=-1
Divide -3 by 3 to get -1.
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