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1+x>0 1+x<0
Denominator 1+x cannot be zero since division by zero is not defined. There are two cases.
x>-1
Consider the case when 1+x is positive. Move 1 to the right hand side.
x-2<1+x
The initial inequality does not change the direction when multiplied by 1+x for 1+x>0.
x-x<2+1
Move the terms containing x to the left hand side and all other terms to the right hand side.
0<3
Combine like terms.
x>-1
Consider condition x>-1 specified above.
x<-1
Now consider the case when 1+x is negative. Move 1 to the right hand side.
x-2>1+x
The initial inequality changes the direction when multiplied by 1+x for 1+x<0.
x-x>2+1
Move the terms containing x to the left hand side and all other terms to the right hand side.
0>3
Combine like terms.
x\in \emptyset
Consider condition x<-1 specified above.
x>-1
The final solution is the union of the obtained solutions.