Solve x-12/6-x-y/3-y/6=0

$$\frac{ x-12 }{ 6 } - \frac{ x-y }{ 3 } - \frac{ y }{ 6 } = 0$$

Solve for x

$$x=y-12$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 6,3.

$$x-12-2\left(x-y\right)-y=0$$

Use the distributive property to multiply -2 by x-y.

$$x-12-2x+2y-y=0$$

Combine x and -2x to get -x.

$$-x-12+2y-y=0$$

Add 12 to both sides. Anything plus zero gives itself.

$$-x+2y-y=12$$

Subtract 2y from both sides.

$$-x-y=12-2y$$

Add y to both sides.

$$-x=12-2y+y$$

Combine -2y and y to get -y.

$$-x=12-y$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{12-y}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{12-y}{-1}$$

Divide 12-y by -1.

$$x=y-12$$

Solve for y

$$y=x+12$$

Solution Steps

Multiply both sides of the equation by 6, the least common multiple of 6,3.

$$x-12-2\left(x-y\right)-y=0$$

Use the distributive property to multiply -2 by x-y.

$$x-12-2x+2y-y=0$$

Combine x and -2x to get -x.

$$-x-12+2y-y=0$$

Add x to both sides. Anything plus zero gives itself.

$$-12+2y-y=x$$

Add 12 to both sides.

$$2y-y=x+12$$

Combine 2y and -y to get y.

$$y=x+12$$