Solve for x
x=\frac{2y+1}{1-3y}
y\neq \frac{1}{3}
Solve for y
y=\frac{x-1}{3x+2}
x\neq -\frac{2}{3}
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x-1=y\left(3x+2\right)
Variable x cannot be equal to -\frac{2}{3} since division by zero is not defined. Multiply both sides of the equation by 3x+2.
x-1=3yx+2y
Use the distributive property to multiply y by 3x+2.
x-1-3yx=2y
Subtract 3yx from both sides.
x-3yx=2y+1
Add 1 to both sides.
\left(1-3y\right)x=2y+1
Combine all terms containing x.
\frac{\left(1-3y\right)x}{1-3y}=\frac{2y+1}{1-3y}
Divide both sides by -3y+1.
x=\frac{2y+1}{1-3y}
Dividing by -3y+1 undoes the multiplication by -3y+1.
x=\frac{2y+1}{1-3y}\text{, }x\neq -\frac{2}{3}
Variable x cannot be equal to -\frac{2}{3}.
x-1=y\left(3x+2\right)
Multiply both sides of the equation by 3x+2.
x-1=3yx+2y
Use the distributive property to multiply y by 3x+2.
3yx+2y=x-1
Swap sides so that all variable terms are on the left hand side.
\left(3x+2\right)y=x-1
Combine all terms containing y.
\frac{\left(3x+2\right)y}{3x+2}=\frac{x-1}{3x+2}
Divide both sides by 3x+2.
y=\frac{x-1}{3x+2}
Dividing by 3x+2 undoes the multiplication by 3x+2.
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