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x\left(x+1\right)=646\times 2
Multiply both sides by 2.
x^{2}+x=646\times 2
Use the distributive property to multiply x by x+1.
x^{2}+x=1292
Multiply 646 and 2 to get 1292.
x^{2}+x-1292=0
Subtract 1292 from both sides.
x=\frac{-1±\sqrt{1^{2}-4\left(-1292\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 1 for b, and -1292 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-1±\sqrt{1-4\left(-1292\right)}}{2}
Square 1.
x=\frac{-1±\sqrt{1+5168}}{2}
Multiply -4 times -1292.
x=\frac{-1±\sqrt{5169}}{2}
Add 1 to 5168.
x=\frac{\sqrt{5169}-1}{2}
Now solve the equation x=\frac{-1±\sqrt{5169}}{2} when ± is plus. Add -1 to \sqrt{5169}.
x=\frac{-\sqrt{5169}-1}{2}
Now solve the equation x=\frac{-1±\sqrt{5169}}{2} when ± is minus. Subtract \sqrt{5169} from -1.
x=\frac{\sqrt{5169}-1}{2} x=\frac{-\sqrt{5169}-1}{2}
The equation is now solved.
x\left(x+1\right)=646\times 2
Multiply both sides by 2.
x^{2}+x=646\times 2
Use the distributive property to multiply x by x+1.
x^{2}+x=1292
Multiply 646 and 2 to get 1292.
x^{2}+x+\left(\frac{1}{2}\right)^{2}=1292+\left(\frac{1}{2}\right)^{2}
Divide 1, the coefficient of the x term, by 2 to get \frac{1}{2}. Then add the square of \frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+x+\frac{1}{4}=1292+\frac{1}{4}
Square \frac{1}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}+x+\frac{1}{4}=\frac{5169}{4}
Add 1292 to \frac{1}{4}.
\left(x+\frac{1}{2}\right)^{2}=\frac{5169}{4}
Factor x^{2}+x+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{1}{2}\right)^{2}}=\sqrt{\frac{5169}{4}}
Take the square root of both sides of the equation.
x+\frac{1}{2}=\frac{\sqrt{5169}}{2} x+\frac{1}{2}=-\frac{\sqrt{5169}}{2}
Simplify.
x=\frac{\sqrt{5169}-1}{2} x=\frac{-\sqrt{5169}-1}{2}
Subtract \frac{1}{2} from both sides of the equation.