Solve for x
x=\frac{5y}{91}
y\neq 0
Solve for y
y=\frac{91x}{5}
x\neq 0
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\frac{x+y}{x}=\frac{96}{5}
Divide both sides by 5.
5\left(x+y\right)=96x
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 5x, the least common multiple of x,5.
5x+5y=96x
Use the distributive property to multiply 5 by x+y.
5x+5y-96x=0
Subtract 96x from both sides.
-91x+5y=0
Combine 5x and -96x to get -91x.
-91x=-5y
Subtract 5y from both sides. Anything subtracted from zero gives its negation.
\frac{-91x}{-91}=-\frac{5y}{-91}
Divide both sides by -91.
x=-\frac{5y}{-91}
Dividing by -91 undoes the multiplication by -91.
x=\frac{5y}{91}
Divide -5y by -91.
x=\frac{5y}{91}\text{, }x\neq 0
Variable x cannot be equal to 0.
\frac{x+y}{x}=\frac{96}{5}
Divide both sides by 5.
5\left(x+y\right)=96x
Multiply both sides of the equation by 5x, the least common multiple of x,5.
5x+5y=96x
Use the distributive property to multiply 5 by x+y.
5y=96x-5x
Subtract 5x from both sides.
5y=91x
Combine 96x and -5x to get 91x.
\frac{5y}{5}=\frac{91x}{5}
Divide both sides by 5.
y=\frac{91x}{5}
Dividing by 5 undoes the multiplication by 5.
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