Solve for x
x=-7
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\left(x-5\right)\left(x+4\right)=\left(x+3\right)\left(x-2\right)
Variable x cannot be equal to any of the values -3,5 since division by zero is not defined. Multiply both sides of the equation by \left(x-5\right)\left(x+3\right), the least common multiple of x+3,x-5.
x^{2}-x-20=\left(x+3\right)\left(x-2\right)
Use the distributive property to multiply x-5 by x+4 and combine like terms.
x^{2}-x-20=x^{2}+x-6
Use the distributive property to multiply x+3 by x-2 and combine like terms.
x^{2}-x-20-x^{2}=x-6
Subtract x^{2} from both sides.
-x-20=x-6
Combine x^{2} and -x^{2} to get 0.
-x-20-x=-6
Subtract x from both sides.
-2x-20=-6
Combine -x and -x to get -2x.
-2x=-6+20
Add 20 to both sides.
-2x=14
Add -6 and 20 to get 14.
x=\frac{14}{-2}
Divide both sides by -2.
x=-7
Divide 14 by -2 to get -7.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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