Solve x+3/4+x+1/3^=2

$$\frac{ x+3 }{ 4 } + \frac{ x+1 }{ { 3 }^{ } } = 2$$

Solve for x

$$x = \frac{11}{7} = 1\frac{4}{7} \approx 1.571428571$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 4.

$$x+3+\frac{4}{3}\left(x+1\right)=8$$

Use the distributive property to multiply \frac{4}{3} by x+1.

$$x+3+\frac{4}{3}x+\frac{4}{3}=8$$

Combine x and \frac{4}{3}x to get \frac{7}{3}x.

$$\frac{7}{3}x+3+\frac{4}{3}=8$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{7}{3}x+\frac{9}{3}+\frac{4}{3}=8$$

Since \frac{9}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.

$$\frac{7}{3}x+\frac{9+4}{3}=8$$

Add 9 and 4 to get 13.

$$\frac{7}{3}x+\frac{13}{3}=8$$

Subtract \frac{13}{3} from both sides.

$$\frac{7}{3}x=8-\frac{13}{3}$$

Convert 8 to fraction \frac{24}{3}.

$$\frac{7}{3}x=\frac{24}{3}-\frac{13}{3}$$

Since \frac{24}{3} and \frac{13}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7}{3}x=\frac{24-13}{3}$$

Subtract 13 from 24 to get 11.

$$\frac{7}{3}x=\frac{11}{3}$$

Multiply both sides by \frac{3}{7}, the reciprocal of \frac{7}{3}.

$$x=\frac{11}{3}\times \frac{3}{7}$$

Multiply \frac{11}{3} times \frac{3}{7} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{11\times 3}{3\times 7}$$

Cancel out 3 in both numerator and denominator.

$$x=\frac{11}{7}$$