Solve x+3/1+3=y+4/6+4

$$\frac{ x+3 }{ 1+3 } = \frac{ y+4 }{ 6+4 }$$

Solve for x

$$x=\frac{2y-7}{5}$$

Steps for Solving Linear Equation

Add 1 and 3 to get 4.

$$\frac{x+3}{4}=\frac{y+4}{6+4}$$

Add 6 and 4 to get 10.

$$\frac{x+3}{4}=\frac{y+4}{10}$$

Divide each term of x+3 by 4 to get \frac{1}{4}x+\frac{3}{4}.

$$\frac{1}{4}x+\frac{3}{4}=\frac{y+4}{10}$$

Divide each term of y+4 by 10 to get \frac{1}{10}y+\frac{2}{5}.

$$\frac{1}{4}x+\frac{3}{4}=\frac{1}{10}y+\frac{2}{5}$$

Subtract \frac{3}{4} from both sides.

$$\frac{1}{4}x=\frac{1}{10}y+\frac{2}{5}-\frac{3}{4}$$

Subtract \frac{3}{4} from \frac{2}{5} to get -\frac{7}{20}.

$$\frac{1}{4}x=\frac{1}{10}y-\frac{7}{20}$$

The equation is in standard form.

$$\frac{1}{4}x=\frac{y}{10}-\frac{7}{20}$$

Multiply both sides by 4.

$$\frac{\frac{1}{4}x}{\frac{1}{4}}=\frac{\frac{y}{10}-\frac{7}{20}}{\frac{1}{4}}$$

Dividing by \frac{1}{4} undoes the multiplication by \frac{1}{4}.

$$x=\frac{\frac{y}{10}-\frac{7}{20}}{\frac{1}{4}}$$

Divide \frac{y}{10}-\frac{7}{20} by \frac{1}{4} by multiplying \frac{y}{10}-\frac{7}{20} by the reciprocal of \frac{1}{4}.

$$x=\frac{2y-7}{5}$$

Solve for y

$$y=\frac{5x+7}{2}$$

Steps for Solving Linear Equation

Add 1 and 3 to get 4.

$$\frac{x+3}{4}=\frac{y+4}{6+4}$$

Add 6 and 4 to get 10.

$$\frac{x+3}{4}=\frac{y+4}{10}$$

Divide each term of x+3 by 4 to get \frac{1}{4}x+\frac{3}{4}.

$$\frac{1}{4}x+\frac{3}{4}=\frac{y+4}{10}$$

Divide each term of y+4 by 10 to get \frac{1}{10}y+\frac{2}{5}.

$$\frac{1}{4}x+\frac{3}{4}=\frac{1}{10}y+\frac{2}{5}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{10}y+\frac{2}{5}=\frac{1}{4}x+\frac{3}{4}$$

Subtract \frac{2}{5} from both sides.

$$\frac{1}{10}y=\frac{1}{4}x+\frac{3}{4}-\frac{2}{5}$$

Subtract \frac{2}{5} from \frac{3}{4} to get \frac{7}{20}.

$$\frac{1}{10}y=\frac{1}{4}x+\frac{7}{20}$$

The equation is in standard form.

$$\frac{1}{10}y=\frac{x}{4}+\frac{7}{20}$$

Multiply both sides by 10.

$$\frac{\frac{1}{10}y}{\frac{1}{10}}=\frac{\frac{x}{4}+\frac{7}{20}}{\frac{1}{10}}$$

Dividing by \frac{1}{10} undoes the multiplication by \frac{1}{10}.

$$y=\frac{\frac{x}{4}+\frac{7}{20}}{\frac{1}{10}}$$

Divide \frac{x}{4}+\frac{7}{20} by \frac{1}{10} by multiplying \frac{x}{4}+\frac{7}{20} by the reciprocal of \frac{1}{10}.

$$y=\frac{5x+7}{2}$$