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2\left(x+1\right)-5\left(x-2\right)\geq 0
Multiply both sides of the equation by 10, the least common multiple of 5,2. Since 10 is positive, the inequality direction remains the same.
2x+2-5\left(x-2\right)\geq 0
Use the distributive property to multiply 2 by x+1.
2x+2-5x+10\geq 0
Use the distributive property to multiply -5 by x-2.
-3x+2+10\geq 0
Combine 2x and -5x to get -3x.
-3x+12\geq 0
Add 2 and 10 to get 12.
-3x\geq -12
Subtract 12 from both sides. Anything subtracted from zero gives its negation.
x\leq \frac{-12}{-3}
Divide both sides by -3. Since -3 is negative, the inequality direction is changed.
x\leq 4
Divide -12 by -3 to get 4.