Solve x+206/36x/3x+frac{412{36}x}

$$\frac{ x+ \frac{ 206 }{ 36 } x }{ 3x+ \frac{ 412 }{ 36 } x }$$

Evaluate

$$\frac{121}{260}\approx 0.465384615$$

Solution Steps

Reduce the fraction \frac{206}{36} to lowest terms by extracting and canceling out 2.

$$\frac{x+\frac{103}{18}x}{3x+\frac{412}{36}x}$$

Combine x and \frac{103}{18}x to get \frac{121}{18}x.

$$\frac{\frac{121}{18}x}{3x+\frac{412}{36}x}$$

Reduce the fraction \frac{412}{36} to lowest terms by extracting and canceling out 4.

$$\frac{\frac{121}{18}x}{3x+\frac{103}{9}x}$$

Combine 3x and \frac{103}{9}x to get \frac{130}{9}x.

$$\frac{\frac{121}{18}x}{\frac{130}{9}x}$$

Cancel out x in both numerator and denominator.

$$\frac{\frac{121}{18}}{\frac{130}{9}}$$

Divide \frac{121}{18} by \frac{130}{9} by multiplying \frac{121}{18} by the reciprocal of \frac{130}{9}.

$$\frac{121}{18}\times \frac{9}{130}$$

Multiply \frac{121}{18} times \frac{9}{130} by multiplying numerator times numerator and denominator times denominator.

$$\frac{121\times 9}{18\times 130}$$

Do the multiplications in the fraction \frac{121\times 9}{18\times 130}.

$$\frac{1089}{2340}$$

Reduce the fraction \frac{1089}{2340} to lowest terms by extracting and canceling out 9.

$$\frac{121}{260}$$

Factor

$$\frac{11 ^ {2}}{2 ^ {2} \cdot 5 \cdot 13} = 0.4653846153846154$$