Solve for x
x=\frac{8\left(y+6\right)}{3}
y\neq -6
Solve for y
y=\frac{3\left(x-16\right)}{8}
x\neq 0
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3x=8\left(y+6\right)
Multiply both sides of the equation by 3\left(y+6\right), the least common multiple of y+6,3.
3x=8y+48
Use the distributive property to multiply 8 by y+6.
\frac{3x}{3}=\frac{8y+48}{3}
Divide both sides by 3.
x=\frac{8y+48}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{8y}{3}+16
Divide 48+8y by 3.
3x=8\left(y+6\right)
Variable y cannot be equal to -6 since division by zero is not defined. Multiply both sides of the equation by 3\left(y+6\right), the least common multiple of y+6,3.
3x=8y+48
Use the distributive property to multiply 8 by y+6.
8y+48=3x
Swap sides so that all variable terms are on the left hand side.
8y=3x-48
Subtract 48 from both sides.
\frac{8y}{8}=\frac{3x-48}{8}
Divide both sides by 8.
y=\frac{3x-48}{8}
Dividing by 8 undoes the multiplication by 8.
y=\frac{3x}{8}-6
Divide -48+3x by 8.
y=\frac{3x}{8}-6\text{, }y\neq -6
Variable y cannot be equal to -6.
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