Solve for x
x\leq 10
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2x-10\leq 20-x
Multiply both sides of the equation by 10, the least common multiple of 5,10. Since 10 is positive, the inequality direction remains the same.
2x-10+x\leq 20
Add x to both sides.
3x-10\leq 20
Combine 2x and x to get 3x.
3x\leq 20+10
Add 10 to both sides.
3x\leq 30
Add 20 and 10 to get 30.
x\leq \frac{30}{3}
Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.
x\leq 10
Divide 30 by 3 to get 10.
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Limits
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