Solve for x
x=-\frac{2y}{3}+4
Solve for y
y=-\frac{3x}{2}+6
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3x+2y=12
Multiply both sides of the equation by 12, the least common multiple of 4,6.
3x=12-2y
Subtract 2y from both sides.
\frac{3x}{3}=\frac{12-2y}{3}
Divide both sides by 3.
x=\frac{12-2y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{2y}{3}+4
Divide 12-2y by 3.
3x+2y=12
Multiply both sides of the equation by 12, the least common multiple of 4,6.
2y=12-3x
Subtract 3x from both sides.
\frac{2y}{2}=\frac{12-3x}{2}
Divide both sides by 2.
y=\frac{12-3x}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3x}{2}+6
Divide 12-3x by 2.
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