Solve x/3-1/7+9/x*5^2

$$\frac{ x }{ 3 } - \frac{ 1 }{ 7 } + \frac{ 9 }{ x } \times { 5 }^{ 2 }$$

Evaluate

$$\frac{x}{3}-\frac{1}{7}+\frac{225}{x}$$

Short Solution Steps

Calculate 5 to the power of 2 and get 25.

$$\frac{x}{3}-\frac{1}{7}+\frac{9}{x}\times 25$$

Express \frac{9}{x}\times 25 as a single fraction.

$$\frac{x}{3}-\frac{1}{7}+\frac{9\times 25}{x}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 3 and 7 is 21. Multiply \frac{x}{3} times \frac{7}{7}. Multiply \frac{1}{7} times \frac{3}{3}.

$$\frac{7x}{21}-\frac{3}{21}+\frac{9\times 25}{x}$$

Since \frac{7x}{21} and \frac{3}{21} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7x-3}{21}+\frac{9\times 25}{x}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 21 and x is 21x. Multiply \frac{7x-3}{21} times \frac{x}{x}. Multiply \frac{9\times 25}{x} times \frac{21}{21}.

$$\frac{\left(7x-3\right)x}{21x}+\frac{21\times 9\times 25}{21x}$$

Since \frac{\left(7x-3\right)x}{21x} and \frac{21\times 9\times 25}{21x} have the same denominator, add them by adding their numerators.

$$\frac{\left(7x-3\right)x+21\times 9\times 25}{21x}$$

Do the multiplications in \left(7x-3\right)x+21\times 9\times 25.

$$\frac{7x^{2}-3x+4725}{21x}$$

Factor

$$\frac{7x^{2}-3x+4725}{21x}$$