Solve x/2--7^0=sqrt{-5^2--3^2}

$$\frac{ x }{ 2 } - { -7 }^{ 0 } = \sqrt{ { -5 }^{ 2 } - { -3 }^{ 2 } }$$

Solve for x

$$x=10$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$x-2\left(-7\right)^{0}=2\sqrt{\left(-5\right)^{2}-\left(-3\right)^{2}}$$

Calculate -7 to the power of 0 and get 1.

$$x-2\times 1=2\sqrt{\left(-5\right)^{2}-\left(-3\right)^{2}}$$

Multiply 2 and 1 to get 2.

$$x-2=2\sqrt{\left(-5\right)^{2}-\left(-3\right)^{2}}$$

Calculate -5 to the power of 2 and get 25.

$$x-2=2\sqrt{25-\left(-3\right)^{2}}$$

Calculate -3 to the power of 2 and get 9.

$$x-2=2\sqrt{25-9}$$

Subtract 9 from 25 to get 16.

$$x-2=2\sqrt{16}$$

Calculate the square root of 16 and get 4.

$$x-2=2\times 4$$

Multiply 2 and 4 to get 8.

$$x-2=8$$

Add 2 to both sides.

$$x=8+2$$

Add 8 and 2 to get 10.

$$x=10$$