Solve for x
x\leq -18
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3x+12\leq 2x-6
Multiply both sides of the equation by 6, the least common multiple of 2,3. Since 6 is positive, the inequality direction remains the same.
3x+12-2x\leq -6
Subtract 2x from both sides.
x+12\leq -6
Combine 3x and -2x to get x.
x\leq -6-12
Subtract 12 from both sides.
x\leq -18
Subtract 12 from -6 to get -18.
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