Solve x/2+frac{sqrt{3}}{2}y=2

$$\frac{ x }{ 2 } + \frac{ \sqrt{ 3 } }{ 2 } y=2$$

Solve for x

$$x=-\sqrt{3}y+4$$

Solution Steps

Multiply both sides of the equation by 2.

$$x+\sqrt{3}y=4$$

Subtract \sqrt{3}y from both sides.

$$x=4-\sqrt{3}y$$

Reorder the terms.

$$x=-\sqrt{3}y+4$$

Solve for y

$$y=-\frac{\sqrt{3}\left(x-4\right)}{3}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$x+\sqrt{3}y=4$$

Subtract x from both sides.

$$\sqrt{3}y=4-x$$

Divide both sides by \sqrt{3}.

$$\frac{\sqrt{3}y}{\sqrt{3}}=\frac{4-x}{\sqrt{3}}$$

Dividing by \sqrt{3} undoes the multiplication by \sqrt{3}.

$$y=\frac{4-x}{\sqrt{3}}$$

Divide 4-x by \sqrt{3}.

$$y=\frac{\sqrt{3}\left(4-x\right)}{3}$$