Solve 9.8(11.3*10^3-1.31*10^3)*4*0.0047/0.7

$$\frac{ 9.8(11.3 \times { 10 }^{ 3 } -1.31 \times { 10 }^{ 3 } ) \times 4 \times 0.0047 }{ 0.7 }$$

Evaluate

$$2629.368$$

Solution Steps

Calculate 10 to the power of 3 and get 1000.

$$\frac{9.8\left(11.3\times 1000-1.31\times 10^{3}\right)\times 4\times 0.0047}{0.7}$$

Multiply 11.3 and 1000 to get 11300.

$$\frac{9.8\left(11300-1.31\times 10^{3}\right)\times 4\times 0.0047}{0.7}$$

Calculate 10 to the power of 3 and get 1000.

$$\frac{9.8\left(11300-1.31\times 1000\right)\times 4\times 0.0047}{0.7}$$

Multiply 1.31 and 1000 to get 1310.

$$\frac{9.8\left(11300-1310\right)\times 4\times 0.0047}{0.7}$$

Subtract 1310 from 11300 to get 9990.

$$\frac{9.8\times 9990\times 4\times 0.0047}{0.7}$$

Multiply 9.8 and 9990 to get 97902.

$$\frac{97902\times 4\times 0.0047}{0.7}$$

Multiply 97902 and 4 to get 391608.

$$\frac{391608\times 0.0047}{0.7}$$

Multiply 391608 and 0.0047 to get 1840.5576.

$$\frac{1840.5576}{0.7}$$

Expand \frac{1840.5576}{0.7} by multiplying both numerator and the denominator by 10000.

$$\frac{18405576}{7000}$$

Reduce the fraction \frac{18405576}{7000} to lowest terms by extracting and canceling out 56.

$$\frac{328671}{125}$$

Factor

$$\frac{7 \cdot 37 \cdot 47 \cdot 3 ^ {3}}{5 ^ {3}} = 2629\frac{46}{125} = 2629.368$$