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15\times 9=xx
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 15x, the least common multiple of x,15.
15\times 9=x^{2}
Multiply x and x to get x^{2}.
135=x^{2}
Multiply 15 and 9 to get 135.
x^{2}=135
Swap sides so that all variable terms are on the left hand side.
x=3\sqrt{15} x=-3\sqrt{15}
Take the square root of both sides of the equation.
15\times 9=xx
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 15x, the least common multiple of x,15.
15\times 9=x^{2}
Multiply x and x to get x^{2}.
135=x^{2}
Multiply 15 and 9 to get 135.
x^{2}=135
Swap sides so that all variable terms are on the left hand side.
x^{2}-135=0
Subtract 135 from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-135\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -135 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-135\right)}}{2}
Square 0.
x=\frac{0±\sqrt{540}}{2}
Multiply -4 times -135.
x=\frac{0±6\sqrt{15}}{2}
Take the square root of 540.
x=3\sqrt{15}
Now solve the equation x=\frac{0±6\sqrt{15}}{2} when ± is plus.
x=-3\sqrt{15}
Now solve the equation x=\frac{0±6\sqrt{15}}{2} when ± is minus.
x=3\sqrt{15} x=-3\sqrt{15}
The equation is now solved.