Solve 9/98+6/49+5

$$\frac{ 9 }{ 98 } + \frac{ 6 }{ 49 } +5$$

Evaluate

$$\frac{73}{14}\approx 5.214285714$$

Solution Steps

Least common multiple of 98 and 49 is 98. Convert \frac{9}{98} and \frac{6}{49} to fractions with denominator 98.

$$\frac{9}{98}+\frac{12}{98}+5$$

Since \frac{9}{98} and \frac{12}{98} have the same denominator, add them by adding their numerators.

$$\frac{9+12}{98}+5$$

Add 9 and 12 to get 21.

$$\frac{21}{98}+5$$

Reduce the fraction \frac{21}{98} to lowest terms by extracting and canceling out 7.

$$\frac{3}{14}+5$$

Convert 5 to fraction \frac{70}{14}.

$$\frac{3}{14}+\frac{70}{14}$$

Since \frac{3}{14} and \frac{70}{14} have the same denominator, add them by adding their numerators.

$$\frac{3+70}{14}$$

Add 3 and 70 to get 73.

$$\frac{73}{14}$$

Factor

$$\frac{73}{2 \cdot 7} = 5\frac{3}{14} = 5.214285714285714$$