Solve 9/5-9/5*-1/5/frac{12{5}}

$$\frac{ 9 }{ 5 } - \frac{ 9 }{ 5 } \times - \frac{ \frac{ 1 }{ 5 } }{ \frac{ 12 }{ 5 } }$$

Evaluate

$$\frac{39}{20}=1.95$$

Solution Steps

Divide \frac{1}{5} by \frac{12}{5} by multiplying \frac{1}{5} by the reciprocal of \frac{12}{5}.

$$\frac{9}{5}-\frac{9}{5}\left(-\frac{1}{5}\times \frac{5}{12}\right)$$

Multiply \frac{1}{5} times \frac{5}{12} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9}{5}-\frac{9}{5}\left(-\frac{1\times 5}{5\times 12}\right)$$

Cancel out 5 in both numerator and denominator.

$$\frac{9}{5}-\frac{9}{5}\left(-\frac{1}{12}\right)$$

Multiply \frac{9}{5} times -\frac{1}{12} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9}{5}-\frac{9\left(-1\right)}{5\times 12}$$

Do the multiplications in the fraction \frac{9\left(-1\right)}{5\times 12}.

$$\frac{9}{5}-\frac{-9}{60}$$

Reduce the fraction \frac{-9}{60} to lowest terms by extracting and canceling out 3.

$$\frac{9}{5}-\left(-\frac{3}{20}\right)$$

The opposite of -\frac{3}{20} is \frac{3}{20}.

$$\frac{9}{5}+\frac{3}{20}$$

Least common multiple of 5 and 20 is 20. Convert \frac{9}{5} and \frac{3}{20} to fractions with denominator 20.

$$\frac{36}{20}+\frac{3}{20}$$

Since \frac{36}{20} and \frac{3}{20} have the same denominator, add them by adding their numerators.

$$\frac{36+3}{20}$$

Add 36 and 3 to get 39.

$$\frac{39}{20}$$

Factor

$$\frac{3 \cdot 13}{2 ^ {2} \cdot 5} = 1\frac{19}{20} = 1.95$$