Solve 9/4-3/4(1/3)+4/3*3-2)+frac{2}{3}

$$\frac{ 9 }{ 4 } - \frac{ 3 }{ 4 } ( \frac{ 1 }{ 3 } )+ \frac{ 4 }{ 3 } \times 3-2)+ \frac{ 2 }{ 3 }$$

Evaluate

$$4$$

Solution Steps

Multiply \frac{3}{4} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9}{4}-\frac{3\times 1}{4\times 3}+\frac{4}{3}\times 3-2$$

Cancel out 3 in both numerator and denominator.

$$\frac{9}{4}-\frac{1}{4}+\frac{4}{3}\times 3-2$$

Since \frac{9}{4} and \frac{1}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-1}{4}+\frac{4}{3}\times 3-2$$

Subtract 1 from 9 to get 8.

$$\frac{8}{4}+\frac{4}{3}\times 3-2$$

Divide 8 by 4 to get 2.

$$2+\frac{4}{3}\times 3-2$$

Cancel out 3 and 3.

$$2+4-2$$

Add 2 and 4 to get 6.

$$6-2$$

Subtract 2 from 6 to get 4.

$$4$$

Factor

$$2^{2}$$