Solve 9/3+x=6/3-x

$$\frac{ 9 }{ 3+x } = \frac{ 6 }{ 3-x }$$

Solve for x

$$x=\frac{3}{5}=0.6$$

Steps for Solving Linear Equation

Variable x cannot be equal to any of the values -3,3 since division by zero is not defined. Multiply both sides of the equation by \left(x-3\right)\left(x+3\right), the least common multiple of 3+x,3-x.

$$\left(x-3\right)\times 9=-\left(3+x\right)\times 6$$

Use the distributive property to multiply x-3 by 9.

$$9x-27=-\left(3+x\right)\times 6$$

Multiply -1 and 6 to get -6.

$$9x-27=-6\left(3+x\right)$$

Use the distributive property to multiply -6 by 3+x.

$$9x-27=-18-6x$$

Add 6x to both sides.

$$9x-27+6x=-18$$

Combine 9x and 6x to get 15x.

$$15x-27=-18$$

Add 27 to both sides.

$$15x=-18+27$$

Add -18 and 27 to get 9.

$$15x=9$$

Divide both sides by 15.

$$x=\frac{9}{15}$$

Reduce the fraction \frac{9}{15} to lowest terms by extracting and canceling out 3.

$$x=\frac{3}{5}$$