Solve for x
x=-\frac{3y}{8}+\frac{2}{3}
Solve for y
y=-\frac{8x}{3}+\frac{16}{9}
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8x+3y=\frac{4}{3}\times 4
Multiply both sides by 4.
8x+3y=\frac{16}{3}
Multiply \frac{4}{3} and 4 to get \frac{16}{3}.
8x=\frac{16}{3}-3y
Subtract 3y from both sides.
\frac{8x}{8}=\frac{\frac{16}{3}-3y}{8}
Divide both sides by 8.
x=\frac{\frac{16}{3}-3y}{8}
Dividing by 8 undoes the multiplication by 8.
x=-\frac{3y}{8}+\frac{2}{3}
Divide \frac{16}{3}-3y by 8.
8x+3y=\frac{4}{3}\times 4
Multiply both sides by 4.
8x+3y=\frac{16}{3}
Multiply \frac{4}{3} and 4 to get \frac{16}{3}.
3y=\frac{16}{3}-8x
Subtract 8x from both sides.
\frac{3y}{3}=\frac{\frac{16}{3}-8x}{3}
Divide both sides by 3.
y=\frac{\frac{16}{3}-8x}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{8x}{3}+\frac{16}{9}
Divide \frac{16}{3}-8x by 3.
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