Solve 84/912^2*(6*7)+(0.71042857)=

$$\frac{ 84 }{ 9 } { 12 }^{ 2 } \times (6 \times 7)+(0.71042857)=$$

Evaluate

$$56448.71042857$$

Solution Steps

Reduce the fraction \frac{84}{9} to lowest terms by extracting and canceling out 3.

$$\frac{28}{3}\times 12^{2}\times 6\times 7+0.71042857$$

Calculate 12 to the power of 2 and get 144.

$$\frac{28}{3}\times 144\times 6\times 7+0.71042857$$

Express \frac{28}{3}\times 144 as a single fraction.

$$\frac{28\times 144}{3}\times 6\times 7+0.71042857$$

Multiply 28 and 144 to get 4032.

$$\frac{4032}{3}\times 6\times 7+0.71042857$$

Divide 4032 by 3 to get 1344.

$$1344\times 6\times 7+0.71042857$$

Multiply 1344 and 6 to get 8064.

$$8064\times 7+0.71042857$$

Multiply 8064 and 7 to get 56448.

$$56448+0.71042857$$

Add 56448 and 0.71042857 to get 56448.71042857.

$$56448.71042857$$

Factor

$$\frac{5644871042857}{2 ^ {8} \cdot 5 ^ {8}} = 56448\frac{71042857}{100000000} = 56448.71042857$$