Solve 80/3x=40x-80

$$\frac{ 80 }{ 3 } x=40x-80$$

Solve for x

$$x=6$$

Steps for Solving Linear Equation

Subtract 40x from both sides.

$$\frac{80}{3}x-40x=-80$$

Combine \frac{80}{3}x and -40x to get -\frac{40}{3}x.

$$-\frac{40}{3}x=-80$$

Multiply both sides by -\frac{3}{40}, the reciprocal of -\frac{40}{3}.

$$x=-80\left(-\frac{3}{40}\right)$$

Express -80\left(-\frac{3}{40}\right) as a single fraction.

$$x=\frac{-80\left(-3\right)}{40}$$

Multiply -80 and -3 to get 240.

$$x=\frac{240}{40}$$

Divide 240 by 40 to get 6.

$$x=6$$