Solve 80/3+4*32/15+4*243/15

$$\frac{ 80 }{ 3 } + \frac{ 4 \times 32 }{ 15 } + \frac{ 4 \times 243 }{ 15 }$$

Evaluate

$$100$$

Solution Steps

Multiply 4 and 32 to get 128.

$$\frac{80}{3}+\frac{128}{15}+\frac{4\times 243}{15}$$

Least common multiple of 3 and 15 is 15. Convert \frac{80}{3} and \frac{128}{15} to fractions with denominator 15.

$$\frac{400}{15}+\frac{128}{15}+\frac{4\times 243}{15}$$

Since \frac{400}{15} and \frac{128}{15} have the same denominator, add them by adding their numerators.

$$\frac{400+128}{15}+\frac{4\times 243}{15}$$

Add 400 and 128 to get 528.

$$\frac{528}{15}+\frac{4\times 243}{15}$$

Reduce the fraction \frac{528}{15} to lowest terms by extracting and canceling out 3.

$$\frac{176}{5}+\frac{4\times 243}{15}$$

Multiply 4 and 243 to get 972.

$$\frac{176}{5}+\frac{972}{15}$$

Reduce the fraction \frac{972}{15} to lowest terms by extracting and canceling out 3.

$$\frac{176}{5}+\frac{324}{5}$$

Since \frac{176}{5} and \frac{324}{5} have the same denominator, add them by adding their numerators.

$$\frac{176+324}{5}$$

Add 176 and 324 to get 500.

$$\frac{500}{5}$$

Divide 500 by 5 to get 100.

$$100$$

Factor

$$2^{2}\times 5^{2}$$